F={A->B,C->D,B->E}
Lossless Join:
R1(ABE) AND R2(CDE)
(R1 $\bigcap$ R2)^+=R1 OR R2 Then it is lossless join dependecy.
R1 $\cap$ R2=$E^{+}$ which is not R1 or R2.
Hence it is lossy join dependency.
Dependency preserving:
R1(ABE) ---A->BE,B->E,AB->E
R2(CDE)---C->D.
R={A->BE,B->E,AB->E,C->D}
F=R .
Hence it is dependecy preserving.
Hence it is lossy join and dependecy preserving.Option '3' is correct.