in Unknown Category edited by
3,311 views
1 vote
1 vote

Find the normalization transformation that maps a window whose lower left corner is at $(1,1)$ and upper right corner is at $(3,5)$ onto a viewpoint that is the entire normalized device screen

  1. $\begin{pmatrix} \dfrac{1}{2} & 0 & \dfrac{-1}{2} \\ 0 & \dfrac{1}{4} & \dfrac{-1}{4} \\ 0 & 0 & 1 \end{pmatrix} \\$
  2. $\begin{pmatrix} \dfrac{1}{2} & 0 & \dfrac{1}{2} \\ 0 & \dfrac{-1}{4} & \dfrac{1}{4} \\ 1 & 1 & 1 \end{pmatrix} \\$
  3. $\begin{pmatrix} \dfrac{1}{2} & 0 & \dfrac{-1}{2} \\ 0 & \dfrac{1}{4} & \dfrac{1}{4} \\ 1 & 0 & 0 \end{pmatrix} \\$
  4. $\begin{pmatrix} \dfrac{1}{2} & 0 & \dfrac{1}{2} \\ 0 & \dfrac{1}{4} & \dfrac{-1}{4} \\ 1 & 0 & 0 \end{pmatrix}$
in Unknown Category edited by
by
3.3k views

2 Answers

0 votes
0 votes

ans is A

2 Comments

edited by

Hi Prasanjeet can you let me know the reason behind SCALING  Wx-max to 1/2 and Wy-max to 1/4. I mean Co-ordinates of view port window are not mentioned in the question can you please let me know on what basis/logic we are scaling it down to 1/2 and 1/4 so as to bring it down to (1,1). I mean why we are bringing it to 1,1 as viewport coordinates, its no where mentioned in the question. Thanks!!!

0
0
S x and SY how u calculate? Let me know
0
0
0 votes
0 votes
Answer:

Related questions