in Combinatory
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Assume that there are 6 color letters L1, L2, L3, L4, L5 and L6 are to be placed in 6 same color envelop E1, E2, E3, E4, E5 and E6 (one letter for each envelop). The number of possibilities to place exactly one letter in its correct envelop ________.
in Combinatory
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@rohit, keneath rosen Discrete Maths book
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Thanks Manu Thakur.
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Number of derangement $\approx$$\frac{n!}{e} $ = $ \frac{5!}{e} =  264.87$

will work for multiple choices :p if stucked
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