Ace Test Series: Operating System - File System

Question

 

Comments

no one pointer will point to one disk block..so 1k entries in one disk block pointing to 1k blocks of size 4KB...so similarly you have 4such blocks which are storing disk block address..so 4*1k*4KB...directory are storing DBA they are not considered in calculating total size of file system...correct me i am wrong

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Hold on, So total size of file system is total number of blocks it is holding am i right ?

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look addressing we are doing is not a part of file that is done for our own convinience to map some address of file when searching(its kind of index)...file is occupying 16MB only.

Answer 1

No of Addresses that can fit in a single block = Block Size / Disk Address size = 4KB/4B(32 bit) = 1024

In total there are 4 Blocks

therefore it can support -> 4 * 1024 Files = 4096 Files

Answer 2

This question cant be of CN, i think it is of Comp.Org