in Calculus
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0/infinity is determinent form or inderminent form while solving limits
in Calculus
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There are many indeterminate forms like 0/0, infinity/infinity, infinity-infinity, 0xinfinity, 1^infinity, Infinity^infinity etc
But we can apply L' hospital rule only when our limits are in the form of 0/0 or infinity/infinity
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$∞^ ∞$ is Not Indeterminate form.
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yes i did a mistake there..it should be infinity^0

And what is infinity^infinity called?
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2 Answers

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2 votes

No, $\frac{0}{∞}$ is Not considered Indeterminate form. Because  any limit that gives rise to this form will converges to Zero.

See, Not every undefined algebraic expression corresponds to an indeterminate form.  For instance, $∞^∞$, $0^∞$, $1/∞$, $1/0$

etc are Not considered as Indeterminate form.

                                     Why $\frac{0}{∞}$ is Not an Indeterminate Form

 

Proof :  

Let the Expression be $\lim_{}   \frac{f}{g}$.

We will have Two cases. One in which we will fix the numerator and we will apply limit on denominator. And in other case, 

we will  fix the denominator and we will apply limit on numerator .

Case 1 : Fix $f=0$ and let $g$ approach to infinity.

So, We have $\lim_{g \rightarrow ∞}  \,\, \frac{0}{g}$ 

And We can solve it. We will have $\lim_{g \rightarrow ∞}  \,\, \frac{0}{g}$ = 0

Case 2 : Fix $g=∞$ and let $f$ approach to zero.

So, We have $\lim_{f \rightarrow 0}  \,\, \frac{f}{∞}$ 

And We can solve it. We will have $\lim_{f \rightarrow 0}  \,\, \frac{f}{∞}$ = 0

So, We can see, In both cases, limit that gives rise to this form will converges to Zero.



Now, Let me pick any Indeterminate form and Prove it to you that Why that limit is called Indeterminate :

                             Why $\frac{0}{0} $ is an Indeterminate Form

 

Proof :  

Let the Expression be $\lim_{}   \frac{f}{g}$.

We will have Two cases. One in which we will fix the numerator and we will apply limit on denominator. And in other case, 

we will fix the denominator and we will apply limit on numerator .

Case 1 : Fix $f=0$ and let $g$ approach to Zero.

So, We have $\lim_{g \rightarrow 0}  \,\, \frac{0}{g}$ 

And We can solve it. We will have $\lim_{g \rightarrow 0}  \,\, \frac{0}{g}$ = 0

Case 2 : Fix $g=0$ and let $f$ approach to Zero.

So, We have $\lim_{f \rightarrow 0}  \,\, \frac{f}{0}$ 

And We can solve it. We will have $\lim_{f \rightarrow 0}  \,\, \frac{f}{0}$ = $+∞ \,\,or -∞$

So, We can see, For any limit of the Form $\frac{0}{0}$, We have Three different results. Hence, It is Indeterminate form.

4 Comments

@deepak poonia itta acha toh kota mein btatte the...nicely explained...:)
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Thanks Shubham :)
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Nice explanation :)

But I did not get the difference between indeterminate and undefined form. 0/0 and /   are the basic indeterminate forms and rest others can also be reduced to one of these forms. Like for eg: - =1/0-1/0=0/0. But I knew that all of them are called indeterminate forms. Can ypu please explain?

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$1/ $$0$ is Undefined because we can't give its value or assign it some specific value. But any expression of the form $lim_{f \rightarrow 0} 1/f$ =  $∞$ ,Which, in calculus, means that as $f$ approaches to $0$, $1/f$ approaches to $∞$.
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2 votes
2 votes

Lets first clear what is division means.

16/4 means How many four required to make the number 16. Answer is 4, 4 four required 4+4+4+4=16 to make 16

3/0 means How many zero required to make  3. Answer is infinite. You add 0s as infinite still you cannot get 3.

0/0 means how many zero required to make 0. Answer is it can be 1 0s or 2 0s or 3 0s or 1000 0s anything It is indetermine. so this form is indeterminate form.

0/5 means How many five required to make 0. Answer is 0 fives required. Answer is 0.

0/infinity means How many infinity required to make it 0. Answer is 0 infinity required. Answer is 0.

 

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