Scaling matrix is given by
X 0 0
0 Y 0
0 0 1
whereas Translation matrix is given by
1 0 X
0 1 Y
0 0 1
So if we apply scaling first and then translation, we won't end up with the elements which we require in the 3rd column of the given matrix.
Hence translation of vector (1,1) i.e 1 0 1
0 1 1
0 0 1
and then applying scaling vector (2,1) on translated vector gives 2 0 2
0 1 1
0 0 1
Ans is option B.