https://gateoverflow.in/931/gate2003-40
IN THE SOLUTION AT LAST 3 STATEMENTS
0≤−6.
which is definitely inconsistent.
Hence, answer = option (D)
WE PUT 6 HERE THEN IF WE DONT HAVE VALUES MEANS FILL IN THE BLANKS THEN..............
IS THERE ANY METHOD TO SOLVE THIS OR ANYTHING ??????
let assume, minimum degree = 6
===>$\frac{min . |v| }{2} $ ≤ 3.|v| - 6
leads to $\frac{6 . |v| }{2} $ ≤ 3.|v| - 6 ===> 3|v| ≤ 3.|v| - 6 ===> 3|v| - 3|v| ≤ 6 ===> 0 ≤ 6 which is wrong
therefore it can't be 6
@Shaik Masthan ITS JUST HIT AND TRAIL METHOD . I AM GETTING IT.
BUT IF IT IS IN THE FILL IN THE BLANKS THEN .................
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