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The area between the parabola $x^2 = 8y$ and the straight line y= 8 is .

I am getting $128√2$.
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i got area = 128 / 3.
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How u got?

I am integrating along y axis from 0 to 8 and function as 2√(2y)?
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y= 8 and y=x^2 / 8

both meet at x=8  and area of y= 8 with x axis is 64 and y=x^2 /8 is 64/3.

so area between the curves : 64 - 64/3 ==128/3.
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Thanks.

Doing some calculation mistake. BTW and is 256/3.

You are calculating for one side only but u have to calculate for both sides of y axis.
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