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Closure Property
Na462
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Theory of Computation
Sep 9, 2018
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If L1 is CSL and L2 is CFL, then which of the following is correct ?
A.L1' - L2 is CSL always
B. L1 - L2' is CSL always
C. L1 intersection Regular is Regular always
D. L1.L2 is CSL but not CFL
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Na462
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Sep 9, 2018
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Na462
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`JEET
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Nov 10, 2019
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So, what's the correct one now?
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Swapnil Naik
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Nov 10, 2019
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here it seems both A and B are correct, C and D are incorrect.
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`JEET
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Yes.
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If a language L1 is given as anbn and L2 is given as {a,b}* , then the language L1 - L2 will be : regular or CFL and why ? My doubt is that since L2 is a regular language and L1 is CFL and L2 will contain all strings in L1, so ... ). Complement of regular is regular and intersection of CFL with regular is closed and the language will be CFL. Which one is right and why ?
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vaishali jhalani
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How to prove this.. CFL is closed under intersection with regular languages.
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$L = \left \{ a^nb^n \ ; n\geq 0 \ , n \neq 20 \right \}$ is (a) a DCFL (b) a recursive set but not CFL (c) a CFL but not DCFL (d) not a CFL
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