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in Probability recategorized by
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A is the correct answer

here we made three case 

case one when we choose the corner in the first choice then we have to choose it two of adjacent 

$\frac{4}{64}*\frac{2}{63}$

because there are four ways to choose the corner of the chess then each corner have two adjacent

case 2nd

choose a green color box (watch figure)then it adjacent 

$\frac{24}{64}*\frac{3}{63}$

case 3rd

choose an inner box which can have 4 adjacent boxes (in figure blue color)

$\frac{36}{64}*\frac{4}{63}$

adding all three case we will get 1/18

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