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The boolean expression $\overline{A} \cdot B + A \cdot \overline{B}+ A \cdot B$ is equivalenet to

  1. $\overline{A} \cdot B$
  2. $\overline{A+B}$
  3. $A \cdot B$
  4. $A+B$
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A'.B + A.B' + A.B

=A'.B + A.B + A.B'

=B(A' + A) + A.B'

=B + A.B'

=(B+A).(B+B')

=B+A

Option(d)

1 comment

In 2nd last line, I used postulate 4

1
1
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Can also be solved using K-map very easily.

Ans: D

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