in Linear Algebra
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in Linear Algebra
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2 Comments

I'm not sure but  I got   D
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bhai how to calculate co-factor here  ???

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1 Answer

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Eigen values are 1,2,3.

Therefore characteristic equation is   (x-1)(x-2)(x-3)=0

By Cayley-Hamilton Theorem,

  (A-I)(A-2I)(A-3I)=0

 A^3 - 6A^2 + 11A = 6I

Multiplying by A^-1,we get

 A^2 - 6A + 11I = 6A^-1

Therefore,  A^-1 = (A^2 - 6A + 11I)/6

Hence (c)

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