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Integration
ghostman23111
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Calculus
Jan 8, 2019
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How to solve it?
ghostman23111
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Jan 8, 2019
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arvin
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Jan 8, 2019
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multiply both numerator and denominator by 2..
=1/2( 2sinx/(sinx-cosx))= 1/2 * (sinx-cosx) + (sinx+cosx) / (sinx-cosx)
= 1/2 * ( 1+ (sinx+cosx) / (sinx-cosx)) dx
= 1/2 * ( x + ln(sinx-cosx)) answer..
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ghostman23111
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Jan 8, 2019
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Is 2sinx = (sinx-cosx)+(sinx+cosx)?
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arvin
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Jan 8, 2019
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its simple add the rhs simply u will get 2sinx simple logic to resolve or simplify the equation.
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Here is the solution goes..
adeemajain
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Jan 11, 2019
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