in Databases edited by
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in Databases edited by
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Is ans given D?
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2 Answers

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i think answer should be C because we can't say about how many are possible...Please verify me>>
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Each Schedule works on different data item so no need to consider that. here ONLY is shared between all three schedule and only operation is Blind write in all three schedule hence no need to check first read and write – read dependency only rule to keep in mind is last write on A.

Let assume T-1 has last write on A so fix T-1 at last position to follow last write. now T-2 and T-3 can be arranged in 2 ways and order doesn’t matter here because no case of dirty read on A . 

D is correct