ME TEST SERIES

Question

Comments

take e^x lnx = t

differentiate wrt to t

you get

 ( e^x lnx + e^x . 1/x ) dx = dt

now substitute

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integration of the form ex[(f(x) + f'(x)] =exf(x) + c

so D

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D)

simple derivative of it will give ans

Answer 1

D.

Using $\int e^x ( f(x) + f'(x) ) = e^xf(x) + c$

Here take $e^x$ common. Let f(x) = ln x, then f'(x)= 1/x