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in Graph Theory closed by
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Checking for Euler Path

i.A graph has Euler path if exactly two vertices is of odd degree.

if a graph have euler circuit=>all vertices even degree=>euler circuit which already cover euler path. am i correct? i is necessary and sufficient condition?

So for checking Euler path 

we check either

1.Euler Circuit

or 

2.Exactly two odd degree then it will have euler path but not euler circuit.

is it correct?

 

in Graph Theory closed by
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4 Comments

got it tahnks @Magma  @Shubhanshu for Ref

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Euler circuit graphs may contains the vertices of deg = 0

i mean to say, isolated vertices doen't effect the eularity of the graph !
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i mean to say, isolated vertices doen't effect the eularity of the graph !

Yes because Euler circuit is only concerned about edges. 

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