in Linear Algebra retagged by
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24 votes
24 votes

Let $X$ be a square matrix. Consider the following two statements on $X$.

  1. $X$ is invertible
  2. Determinant of $X$ is non-zero

Which one of the following is TRUE?

  1. I implies II; II does not imply I
  2. II implies I; I does not imply II
  3. I does not imply II; II does not imply I
  4. I and II are equivalent statements
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2 Comments

What if matrix is not square matrix
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@val_pro20

The inverse of the non-square matrix doesn't exist.

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7 Answers

26 votes
26 votes
Best answer
Square Matrix is invertible iff it is non-singular.
So both statements are same.Answer is (D).
edited by

4 Comments

edited by

$X^{-1}=\dfrac{Adj(X)}{\mid X\mid}$

$I)$ If $X^{-1}$ exist then $\mid X\mid\:\neq0$.

        $X^{-1}\implies \mid X\mid \:\neq0$

$II)$ If $\mid X\mid\:\neq 0$ then $X^{-1}$ exist.

            $\mid X\mid\:\neq 0\implies X^{-1}$

$X^{-1}$ $ \mid X \mid \neq0$.  $X^{-1}\implies \mid X \mid \neq0$ $\mid X \mid \neq0\implies X^{-1}$
$T$ $T$ $T$ $T$
$T$ $F$ $F$ $T$
$F$ $T$ $T$ $F$
$F$ $F$ $T$ $T$

we can write like this  $X^{-1}$ exist $\textbf{if only if (or) iff}\: \mid X\mid\:\neq0$

 

$X^{-1}$ $\mid X \mid \neq0$

 $\big(X^{-1}\implies \mid X \mid \neq0\big)\wedge \big(\mid X \mid \neq0\implies X^{-1}\big) $

$\equiv\:\: \mid X\mid \:\:\neq 0\Longleftrightarrow X^{-1}$

$T$ $T$ $T$
$T$ $F$ $F$
$F$ $T$ $F$
$F$ $F$ $T$

$I)$ and $II)$ Both are equivalent.

Reference: https://brilliant.org/wiki/matrices/

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If the option I implies II and II implies I given then I think it would be much suitable
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Yes, you think in a simple way, but IIT professor think some other way

actually what you write is correct but what they ask is also correct.

$P\Longleftrightarrow Q\equiv (P\Longrightarrow Q)\wedge (Q\Longrightarrow P)$
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Thanks
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6 votes
6 votes
if a square matrix is invertible then it's determinant is non zero

and vice versa

so, (D) is correct option
3 votes
3 votes
Option D is right. As Inverse(A) = Adj(A) / Mod(A)

 

Therefore, if Mod(A) is 0, the Inverse of a matrix cannot be calculated. Therefore both statements are equivalent to each other
2 votes
2 votes

The inverse of a square matrix A, sometimes called a reciprocal matrix, is a matrix A^(-1) such that

AA^(-1)=I,

 

where I is the identity matrix. Courant and Hilbert (1989, p. 10) use the notation A^_ to denote the inverse matrix.

square matrix A has an inverse iff the determinant |A|!=0 (Lipschutz 1991, p. 45). The so-called invertible matrix theorem is major result in linear algebra which associates the existence of a matrix inverse with a number of other equivalent properties. 

 

http://mathworld.wolfram.com/MatrixInverse.html

Answer:

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