Probability

Question

Let 3 cards are drawn from a pack of 52 cards one by one without replacement then find the prob that

3 cards are drawn out of which 2 are ace Ace and one is King?

Comments

why is simply 4C2*4C1/52C3 wrong here?

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Actually the answer should be 4c2*4c1*3!/52*51*50 ,the reason we do not choose 52c3 is because of conditional probability and also the 3! is not 3!/2! because in probability we consider ace as different so there are 3! Permutations and in selection we cannot do ordering therefore 4c2*4c1

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yes it should be 3! only but not $\frac{3!}{2!}$ due to ACE cards can be differentiate !

Thanks for correcting me @rtalwar