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Twelve percent of all US households are in California. A total of 3.3 percent of all US households earn over 250000 per year, while a total of 6.3 percent California households earn over 250000 per year. If a randomly chosen US household earns over 250,000 per year, what is the probability that it is from California??

P(earn>250000)=0.033

P(California)=0.12

P(earn>250000/California)=0.063

P(earn>250000 and California)=0.12 X 0.063=7.56 * 10^(-3)

Then P(earn>250000 and not in California)=0.033-(7.56 * 10^(-3))=0.02544

Then P(California/earn>250000)=(7.56 * 10^(-3)/(0.033)=0.2291

But the answer given in the instructors manual is .2066

What is wrong with my logic??

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Your ans matches with mine,it seems legit... 🙁
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