Self doubt

Question

How is the problem..

Distribute 5 toys such that each of 3 child get atleast 1

Different from sum of 3 no. X+y+z=5 such that each digit >= 1.

Plz explain ?

Comments

This way for the first case we can manually find the cases but how do we do if the no. To be distributed is large say 12

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shaik bro I meant the questions in the exam will give the hint:). This one is ambiguous.

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@Manoj Kumar Pandey refer Rosen or do combinatorics from here.

Answer 1

don't over think  

this can be done  manually

give all student one toy first

x= 1

y=1

z=1

now you are left with 2 more toys i think you can distribute 2 among three easily

x               y              z

2              0              0

0              2              0

0              0              2

1              1              0

1              0              1

0              1              1

ANS=6

correct me if I am wrong.....