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If $f$ and $fog$ are onto, does it follow that $g$ is onto?Justify your answer.
in Set Theory & Algebra
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Suppose that g ◦ f is surjective. Let z ∈ C. Then since g ◦ f is surjective, there exists x ∈ A such that (g ◦ f)(x) = g(f(x)) = z. Therefore if we let y = f(x) ∈ B, then g(y) = z. Thus g is surjective.

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