Bounded lattice

Question

Can a countable infinite lattice be bounded?

Comments

Yes it can be.

https://math.stackexchange.com/questions/301080/how-can-a-set-be-bounded-and-countably-infinite-at-the-same-time

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@smsubham.   Above link...have two answer...both answer contradictory...

 =  {2^(-k)  /  k is +ve interger}

It's bounded and countable infinite....but it's latiice how???

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Yes.