in Calculus recategorized by
414 views
0 votes
0 votes

Let $f(x) = \dfrac{2x}{x-1}, \: x \neq 1$.  State which of the following statements is true.

  1. For all real $y$, there exists $x$ such that $f(x)=y$
  2. For all real $y \neq 1$, there exists $x$ such that $f(x)=y$
  3. For all real $y \neq 2$, there exists $x$ such that $f(x)=y$
  4. None of the above is true
in Calculus recategorized by
by
414 views

1 Answer

1 vote
1 vote

$f(x)=\frac{2x}{x-1}=y $

$\Rightarrow 2x=yx-1 $

$\Rightarrow x=\frac{1}{y-2}$

Thus $y\neq2$ for x to exist.

Hence Option(C) for all real $y\neq2$, there exists $x$ such that $f(x)=y$

 

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true