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The Newton-Raphson iteration $x_{n+1}=\dfrac{x_{n}}{2}+\dfrac{3}{2x_{n}}$ can be used to solve the equation

  1. $x^{2}=3$
  2. $x^{3}=3$
  3. $x^{2}=2$
  4. $x^{3}=2$

 

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