in Digital Logic
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I think given answer is wrong. can anybody help?

in Digital Logic
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2 Answers

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Best answer

$J_1 = Q_0$ , $K_1  =  Q_0'$ , $Q_1^+ = J_1Q_1' +K_1'Q_1=Q_0Q_1'+Q_0Q_1= Q_0$

$J_0 = Q_1'$, $K_0 = Q_1$ , $Q_0^+ = J_0Q_0' +K_0'Q_0=Q_1'Q_0'+Q_1'Q_0= Q_1'$

  $Q_1^+$ $Q_0^+$
Initially $0$ $0$
CP-1 $0$ $1$
CP-2 $1$ $1$
CP-3 $1$ $0$
CP-4 $0$ $0$

it is a mod$4$ counter, after every $4^{th}$ clock pulse, it will return to initial.

$333$mod$4$ = $1$ , so after $332$ clock pulse it will return to $00$ and on $333^{rd}$ it will reach to $01$.

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An edit is required  K1 = Q0' in 1st line
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done :)
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From the diagram :       J0 =  Q1'        and      K0 = Q1

                                      J1 =  Q0         and      K1 = Q0'

State Daigram from the  above table : 

Initial state is 00 so after 333th clock ->  333 mod 4 =1       so , reached to state 01.

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