UGC NET CSE | June 2013 | Part 3 | Question: 55

Question

Given code word $1110001010$ is to be transmitted with even parity check bit. The encoded word to be transmitted for this code is

• A. $11100010101$
• B. $11100010100$
• C. $1110001010$
• D. $111000101$

Answer 1

i think the answer is A) .

because even parity will make it even no of 1`s , i mean see in the transmitted data 1110001010 there are five 1 which is odd . to make it even it will add extra 1 as parity . so it will be 11100010101 .

Answer 2

Ans is A to make it even parity add one extra bit (1) so that no of one's become even (6)in this case