in Digital Logic
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The clock frequency applied to the digital circuit shown in the figure below is 1 kHz. If the initial state of the output Q of the flip-flop is ‘0’, then the frequency of the output waveform Q in kHz is

  1. 0.25
  2. 0.5
  3. 1
  4. 2
in Digital Logic
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Its mod 2 counter. So its diving the clock frequency by 2 right ?
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Image of Time Cycle Graph

I hope this can explain you the solution more easily.

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1 Answer

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From the given circuit ,X=1, so T toggles for every negative edge.

if you draw the waveform , clock will get doubled. so frequencey will gets reduce to half.

therefore the answer for this problem becomes 0.5KHz,