I could not understand here both the outputs point to D3 bit . How to proceed in this scenario ?
If we consider (clock + and) combination as a clock.
then after first clock o/p - 0101
now onwards the clock will always be 0.
2nd clock o/ - 0101
3rd clock o/p - 0101
hence, B
OPTION (A)...
CLOCK I/P D3 D2 D1 D0
0 0 1 0 1 1
1 0 0 1 0 1
2 0 0 0 1 0
3 1 1 0 0 1
Hence the option 9A) is correct.
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