UGC NET CSE | June 2007 | Part 2 | Question: 11

Question

The following loop in $’C’$:

int i=0;
while (i++<0)i--;

• A. will terminate
• B. will go into an infinite loop
• C. will give compilation error
• D. will never be executed

Comments

Loop will never be executed as the very first condition of the loop is not getting satisfied, so there is no way for this loop to be executed.

Answer 1

In while loop, first i value will compare with 0, then it will get incremented.
So 0 < 0, is certainly false, therefore we never enter while loop,and programme terminate successfully.
option A is correct here.

Comments

yes option a is correct here

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a is ryt

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how many times loop get executed 0 or 1 times condition is false so 9 times right ?

Answer 2

initially i value is equal to 0

Now

While (i++<0)

while(0<0) this will be  false.then it will get incremented and i value become  1

So therefore we never enter in while loop so option B is incorrect

and  program terminate successfully means no compiler error so option C,option D are wrong

option A is correct here.