Option (A) 25 paise
let we have 3 cans having coins as following:
|
A |
B |
C |
Actual Coins |
5 |
10 |
25 |
Possible labeling (1) |
10 |
25 |
5 |
Possible labeling (2) |
25 |
5 |
10 |
Now we have 2 possible labeling. But according to the question, can labelled 25 paise is not having 10 paise coins, therefore labelling (1) is not correct. Hence coins are labelled according to labelling(2). So the can labelled 10 paise actually have 25 paise coins.