NIELIT 2016 MAR Scientist C - Section C: 38

Question

How many bits are required to encode all twenty six letters, ten symbols, and ten numerals?

• A. $5$
• B. $6$
• C. $7$
• D. $46$

Answer 1

26 letters + 10 symbols + 10 numerals = 46
any binary code is represented in powers of 2

5 BIT=2^5=32

6 BIT=2 ^6 =64

7 BIT=2^7=128

In 6 bit  is sufficient we can can represent the 46 thing uniquely..

option should be B.

Answer 2

In 6 bit  is sufficient we can can represent the 46 thing uniquely..

option -- B