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Example: 

11110100000111 should be accepted. There are 6 zeros. 6 is divisble by 2 and 3.

 

This machine required at least six states. 

in Theory of Computation recategorized by
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Number of zeros to be divisible by 2 and 3 it should be divisible by 6.

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Answer is-

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if you make initial state q0  as accepting(final) state, 

and maps state q5 to q0 for symbol 0 

then, there is no need of state q6 ( seventh state ).

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