For a cyclic group $\text{G}$ of order $12$, the number of subgroups of $\text{G}$ is
$2$
$6$
$8$
$11$
Lagrange's Theorem: In any finite group G, the order (number of elements) of every subgroup of G divides the order of G.
Here G is the group with an order $12$.So it’s factor are: $1,2,3,4,6,12$
$\therefore 1,2,3,4,6,12$ six subgroups are there.
Lagrange's Theorem-based question:
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