@soujanyareddy13 , Saw your answer. Coud you please ellaborate on that a little more ?
Can’t we treat this problem like digital logic ?
(A+B)(A+B) = ( A or B ) and ( A or B ) = A or B = A + B. – LHS.
For RHS : X.X = X and X.Y = 0 ( if X != Y ) --(1) ---- for this case LHS = RHS – the eqn will be true.
= XY ( if X = Y ) --(2). --- for this case eqn is false – suitable counter example.
Thus in general the eqn does not hold.