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Recent posts in Useful Links

1

IIsc has released dates for written test.

I know nearly all the current/previous toppers are on GO, can you guys please share what to read for the test? I’ve read past year interviews but most of them had choice of subject to get asked on, a liberty we might not have in the written test.

posted Mar 25 in Useful Links zxy123 3,508 views
2
First instance of T2 is arriving at T1, so second instance at 1+7 = T8. Now, if finishes at T9 and next arrival is only at T15.
posted May 2, 2020 in Useful Links dd 1,204 views
3
total schedule = 6!/2!*2!*2! = 90 and every schedule is conflict equal schedule because no cycle in any precedence graph .. by symmetry each serial schedule must have equal no of conflict schedule.. der are 90 schedule and 3! serial schedule.. T1 ----> T2 ----> T3 is one out of 6 serial schedule. so no ofconflict equal schedule which is equal to T1 ----> T2 ----> T3 = 90/6 = 15
posted Apr 24, 2020 in Useful Links Lakshman Patel RJIT 1,266 views
4
every write commit before next operation.. no Write Write conflict so no Lost update problem. no Dirty read also..
posted Apr 24, 2020 in Useful Links Lakshman Patel RJIT
edited Apr 24, 2020 by Lakshman Patel RJIT
1,472 views
5
Car C, we get 3 matching tuples with 1+1+2+2=6 comparisons assuming red is compared first and then green. Now these 3 are compared with 10 tuples in reservation. After this we get 4 dids which we compare with 10 tuples of Driver. I think we get 60-64 comparisons.
posted Apr 18, 2020 in Useful Links Lakshman Patel RJIT
edited Apr 18, 2020 by Lakshman Patel RJIT
2,065 views
6
Answer is option D. Probability of choosing the correct option = $\frac{1}{4}$ Probability of choosing a wrong option = $\frac{3}{4}$ So, expected mark for a question for a student = $\frac{1}{4} \times 1 + \frac{3}{4}\times (-0.25) = 0.0625$ Expected mark for a ... = $0.0625 \times 150 = 9.375$ So, sum total of the expected marks obtained by all $1000$ students = $9.375 \times 1000 = 9375$.
posted Mar 29, 2020 in Useful Links Sambhrant Maurya 1,255 views
7
In CNF, any non-terminal can derive empty string?
posted Mar 15, 2020 in Useful Links blackcloud
edited Mar 25, 2020 by blackcloud
4,466 views
8
Let the sequence be 1 2 3 4 5 6 7 8 (=A) if i select any 3 elements say 3,4,5 (=C) then B would be 1,2,6,7,8 On merging B and C i get 1,2,6,7,8,3,4,5 which is not in ascending order as A.. Can you please explain the case as here i am not getting A on merging....
posted Mar 4, 2020 in Useful Links Lakshman Patel RJIT 1,980 views
9
sir, let if L1={ab} than L2 can be {ba} n here also l1 intersection l2 is empty n l1 union l2 is regular n thus we can say that l2 can be regular n finite. Is this approach right to say that l2 can be regular n finite??
posted Mar 4, 2020 in Useful Links Lakshman Patel RJIT 1,293 views
10
how RHL =0? Is it like 1/(2+infinity) =0.0000023.... =0
posted Feb 26, 2020 in Useful Links Lakshman Patel RJIT 1,087 views
11
present state next state output of multiplexer 000 001 I0 001 011 1 011 010 1 010 110 I1 110 111 I3 111 101 1 101 100 1 100 000 I2 all states are in gray format.. A option..
posted Feb 25, 2020 in Useful Links Lakshman Patel RJIT
edited Feb 26, 2020 by Lakshman Patel RJIT
1,573 views
12
1/(2+e^(1/(x-3))) Is it continuous? where 2<e<3
posted Feb 25, 2020 in Useful Links Lakshman Patel RJIT 637 views
13
I am just reading that Microperations from Morris mano They have explained the concept of 3 state gate which can be used as a multiplexer which have output 1, 0 and high Impedance. what is used of it (I am not getting )
posted Feb 25, 2020 in Useful Links Lakshman Patel RJIT
edited Feb 25, 2020 by Lakshman Patel RJIT
1,377 views
14
Base relative is unsigned but PC relative is signed.
posted Feb 25, 2020 in Useful Links Lakshman Patel RJIT
edited Feb 25, 2020 by Lakshman Patel RJIT
1,398 views
15
SORRY BUT I AM GETTING CONFUSED JUST HOLD ON !
posted Feb 25, 2020 in Useful Links Lakshman Patel RJIT
edited Feb 25, 2020 by Lakshman Patel RJIT
1,086 views
16
Can you explain me this : A table is in second normal form if every attribute is determined by every candidate key , but is not determined by any pure subset of Candidate key ? True or false
posted Feb 25, 2020 in Useful Links Lakshman Patel RJIT
edited Feb 25, 2020 by Lakshman Patel RJIT
1,196 views
17
Cool even i got the same answer so answer is false ! right ?
posted Feb 24, 2020 in Useful Links Lakshman Patel RJIT
edited Feb 25, 2020 by Lakshman Patel RJIT
2,582 views
18
A,B,C,D all are prime attribute so no partial as well as no transitive dependencies..
posted Feb 24, 2020 in Useful Links Lakshman Patel RJIT
edited Feb 24, 2020 by Lakshman Patel RJIT
775 views
19
Hi @laser0 , can u please clarify one doubt of mine. In case of K3,3 , that is also complete bipartite graph , isn't it ? So , is the answer 3 ?
posted Feb 24, 2020 in Useful Links Lakshman Patel RJIT
edited Feb 24, 2020 by Lakshman Patel RJIT
2,104 views
20
Can you explain why the offset in addressing modes need to be a signed integer ?
posted Feb 22, 2020 in Useful Links Lakshman Patel RJIT
edited Mar 23, 2020 by Lakshman Patel RJIT
1,653 views
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