Test by Bikram | Mock GATE | Test 1 | Question: 43

Question

What is the output of the following code snippet?

#include<stdio.h>
int main ( )
{
int x = 2, y = 5;
if (x < y)
   return (x = x+y);
else
   printf (“ GO Mock 1  ”);
   printf(“ Welcome to GO Mock test ”);
}

• A. GO Mock 1
• B. Welcome to GO Mock Test
• C. No output
• D. GO Mock 1Welcome to GO Mock Test

Answer 1

There is no compilation error but there will no output because function is returning a value and if statement is true in this case.

Comments

int main () {}?

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what is your doubt ? specify please .

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should the main function be written as int main()? or just main() is enough?

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what is int here ? it is return type , 

in GCC we write int main() it is a good practice

if you do not write int and just write main() it is fine in GCC, as by default main() takes int in GCC :)

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“ Welcome to GO Mock test ”  never printed for this code. right?

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yes, it will never printed.

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Even for not else case too?

It is under scope of main().So, after else if it will print ?

Will it not give correct output?

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What will print , if "else" part of the program is in execution?

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@srestha

see in this question, if condition part is true but it return some value , Not print anything ..

there will no output because function is returning a value and if statement is true in this case.

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but the time runnung the code, I am getting runtime error

Why?

https://ideone.com/fGjPn6

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because of this line

return (x = x+y);

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why for that line?

More than one return possible in C code. rt?

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yes possible but return for if is not supported ..

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There is no issue with the code. @Srestha you should not use online compiler for learning purpose. Probably they are using return value as means of detecting error.

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can anyone please tell what will happen after return statement??? it will halt??

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main functions return to OS, that means program execution completes !

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@Bikram sir, I feel "Welcome to GO Mock Test" must be printed since in the else statement there are no curly braces which implies that only the first statement preceding the else is a part of else and rest aren't considered as a part of else.
So as per this logic the second line should be printed by default.