Probability - Gravner-3

Question

Toss three fair coins. What is the probability of exactly one Heads$(H)$ ?

Comments

3/8.

The sample space consists of 8 possibilities (since $2^3 = 8$). Out of this, three of them contain exactly one head. Hence.

Answer 1

Toss three fair coins.

Total possibilities are : $HHH$, $HHT$, $HTH$, $HTT$, $THH$, $THT$, $TTH$, $TTT$.

Therefore, there are total $8$ possibilities.

Favourable case (exactly one head) : $HTT$, $THT$, $TTH$

Therefore, there are total $3$ favourable cases out of $8$ possibilities.

P(exactly one Head $(H)$ ) = $\dfrac{3} {8}$

                                            = $\dfrac{\text{Favourable case}} {\text{Total possibilities}}$

                                         = $0.38$