As you have given answer (B) so I guess you know about 2, 3
Now for 1
If we wanna prove that 1 is tautology we will prove by contradiction, we will try to make it false
We know $a\rightarrow b$ is false when $a = 1$ and $b=0$, so let $q = 0$
Now if we take $p=0$ then
$(\lnot p \land(p \lor q)) \rightarrow q = (1 \land(0 \lor 0)) \rightarrow 0 = 0 \rightarrow 0 = 1$
Let $p = 1$
$(\lnot p \land(p \lor q)) \rightarrow q = (0 \land(1 \lor 0)) \rightarrow 0 = 0 \rightarrow 0 = 1$
So (1) can never be false, hence (1) is tautology