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Recent questions tagged disk
6
votes
5
answers
181
GATE CSE 1998 | Question: 25b
Consider a disk with $c$ cylinders, $t$ tracks per cylinder, $s$ sectors per track and a sector length $s_l$. A logical file $d_l$ with fixed record length $r_l$ is stored continuously on this disk starting at location $(c_L, t_L, s_L)$, where ... the formula to calculate the disk address (i.e. cylinder, track and sector) of a logical record n assuming that $r_l=s_l$.
Arjun
asked
in
Operating System
Mar 6, 2016
by
Arjun
3.0k
views
gate1998
operating-system
disk
descriptive
3
votes
3
answers
182
How long does it take to load a 64-KB program from a disk
How long does it take to load a 64-KB program from a disk whose average seek time is 10 msec., whose rotation time is 20 msecs., and whose track holds 32-KB for a 2-KB page size?(How to solve this?)
Purple
asked
in
Operating System
Jan 29, 2016
by
Purple
6.2k
views
secondary-storage
operating-system
disk
page
0
votes
1
answer
183
Percentage Improvement
A magnetic disk has following specs: # 0f tracks=1024 #of sectors/track=512 #of Bytes/sector =512 Disk Rotation speed=7200rpm a)What is the percentage of improvement(approx) in average access time ,if disk speed is doubled? a)16% b)18% c)19% d)None
bahirNaik
asked
in
Operating System
Jan 19, 2016
by
bahirNaik
1.2k
views
co-and-architecture
disk
operating-system
1
vote
2
answers
184
Counting number of block accesses
Given explanation: Please check if given solution is correct or not
shikharV
asked
in
Operating System
Jan 13, 2016
by
shikharV
954
views
operating-system
disk
1
vote
0
answers
185
virtual gate 2016 Disk size
A disk has 16 equidistant tracks. The diameters of the outermost and innermost tracks are 16 cm and 1 cm respectively. The innermost track has got the capacity of 20 MB. The total amount of data which can be stored on the disk if the ... MB (integer value only). {capacity of each track is equal or outermost track has capacity greater than innermost track?? }
khushtak
asked
in
CO and Architecture
Jan 7, 2016
by
khushtak
471
views
co-and-architecture
disk
3
votes
1
answer
186
Estimate the average time to read a random sector from disk
Consider a disk with a rotational rate of 10,000 RPM, an average seek time of 8 ms, and on average of 500 sectors per track. Estimate the average time to read a random sector from disk. (A) 7.012 ms (B) 11.012 ms (C) 14.012 ms (D) 10.012 ms
khushtak
asked
in
Operating System
Jan 6, 2016
by
khushtak
4.4k
views
operating-system
disk
3
votes
1
answer
187
disk management
my approach seek time 30 rotationn latency=10 tranfer time : 64 kb prog page size is 4kb so in 16 pages this prog wiil be accesed through memory since track size is given 32 kb so in 32kb is read in one rtotaion in 20msec so 4kb --------------------------- ... acces 16 pages we need totoal time as : (30+10+2.5)*16=680 msec correct me !! if wrogn thanks..given ans by them is 120.
focus _GATE
asked
in
Operating System
Jan 2, 2016
by
focus _GATE
1.8k
views
operating-system
disk
2
votes
3
answers
188
how many surfaces are required
pls xplain the last line of the qs,"records cannot span 2 records" and what effect does it bring to the problem
resuscitate
asked
in
Operating System
Dec 5, 2015
by
resuscitate
480
views
disk
7
votes
7
answers
189
Calculating disk access time
A program of size 64MB is stored on disk which supports an average seek time of 30ms and rotation time of 20ms. Page size is 4MB and track size is 32MB. If the pages of the program are contiguously placed on disk, then the total time required to load the program from disk in ms is _____ Given answer: 120
shikharV
asked
in
Operating System
Nov 28, 2015
by
shikharV
9.9k
views
operating-system
disk
1
vote
1
answer
190
percentage of time of cpu blockage during dma transfer
Consider a disk drive with following specifications: 16 surfaces, 512 tracks/surface, 512 sectors/sector, 1KB/sector, rot. speed 3000rpm. The disk is operated in cycle stealing mode whereby whenever one byte word is ready it is sent ... cycle time is 40ns. The max. percentage of time that cpu gets blocked during dma operation: 10% 25% 40% 50%
gate_forum
asked
in
CO and Architecture
Nov 14, 2015
by
gate_forum
1.9k
views
co-and-architecture
disk
dma
3
votes
3
answers
191
How to Find Data Transfer Rate?
Consider a disk pack with following specifications - 16 surfaces, 128 tracks/surface, 256 sector/track and 512Bytes/sector. Now, the disk is rotating at 3600RPM, what is the data transfer rate. Please be as elaborative and simplified in your approach of explaining! Thank you, all the nerds on this site!
iarnav
asked
in
Operating System
Nov 13, 2015
by
iarnav
3.9k
views
disk
2
votes
2
answers
192
PAGING
A Program of size 64MB is stored on disk which supports an average seek time of 30ms and rotation time of 20ms.Page size is 4MB and track size is 32MB. if the pages of program are contiguosly placed on disk then what would be the total time required to load the program from disk?
kirti singh
asked
in
Operating System
Nov 6, 2015
by
kirti singh
1.2k
views
operating-system
disk
33
votes
2
answers
193
GATE CSE 1997 | Question: 74
A program $P$ reads and processes $1000$ consecutive records from a sequential file $F$ stored on device $D$ without using any file system facilities. Given the following Size of each record $= 3200$ bytes Access time of $D = 10$ ... a blocking factor of $2$ (i.e., each block on $D$ contains two records of $F$) and $P$ uses one buffer?
go_editor
asked
in
Operating System
Oct 14, 2015
by
go_editor
7.6k
views
gate1997
operating-system
disk
1
vote
1
answer
194
seek time
the seek time of a disk is 30ms.it rotates at the rate of 30 rotations/second.the capacity of each track is 300 words.the access time is (approximately) guys can any one solve this plzzzz...
lohith
asked
in
CO and Architecture
Oct 8, 2015
by
lohith
10.2k
views
disk
3
votes
2
answers
195
ISRO2008-49
The total time to prepare a disk drive mechanism for a block of data to be read from it is seek time latency latency plus seek time transmission time
ajit
asked
in
Operating System
Sep 20, 2015
by
ajit
6.9k
views
isro2008
operating-system
disk
0
votes
1
answer
196
confusion
I was solving few problems on secondary memory . In my book prescribed under our university i found in many solution they had done (2000 *69.14)/8 bytes =17.28 KB but HOW?? IT SHOULD BE 16.87 KB as 1 KB = 1024B not only here another sum had 128 * 100kbps = 13mbps but it should be 12.5 mbps please help me out i am very confused
ANI
asked
in
Operating System
Sep 18, 2015
by
ANI
548
views
operating-system
disk
1
vote
6
answers
197
UGC NET CSE | December 2013 | Part 2 | Question: 49
How much space will be required to store the bit map of a 1.3 GB disk with 512 bytes block size? 332.8 KB 83.6 KB 266.2 KB 256.6 KB
Shimpy Goyal
asked
in
Operating System
Jun 26, 2015
by
Shimpy Goyal
6.7k
views
operating-system
disk
ugcnetcse-dec2013-paper2
49
votes
7
answers
198
GATE CSE 2015 Set 1 | Question: 48
Consider a disk pack with a seek time of $4$ milliseconds and rotational speed of $10000$ rotations per minute (RPM). It has $600$ sectors per track and each sector can store $512$ bytes of data. Consider a file stored in ... sector is half of the time for one complete rotation. The total time (in milliseconds) needed to read the entire file is__________________
makhdoom ghaya
asked
in
Operating System
Feb 13, 2015
by
makhdoom ghaya
20.4k
views
gatecse-2015-set1
operating-system
disk
normal
numerical-answers
44
votes
4
answers
199
GATE CSE 2015 Set 2 | Question: 49
Consider a typical disk that rotates at $15000$ rotations per minute (RPM) and has a transfer rate of $50 \times 10^6$ bytes/sec. If the average seek time of the disk is twice the average rotational delay and the controller's transfer time ... the disk transfer time, the average time (in milliseconds) to read or write a $512$-byte sector of the disk is _____
go_editor
asked
in
Operating System
Feb 13, 2015
by
go_editor
17.6k
views
gatecse-2015-set2
operating-system
disk
normal
numerical-answers
69
votes
5
answers
200
GATE IT 2005 | Question: 81-b
A disk has $8$ equidistant tracks. The diameters of the innermost and outermost tracks are $1$ cm and $8$ cm respectively. The innermost track has a storage capacity of $10$ MB. If the disk has $20$ sectors per track and is currently at the end of the $5^{th}$ sector ... starting from the sector $4$ of the outer-most track? $13.5 \ ms$ $10 \ ms$ $9.5 \ ms$ $20 \ ms$
Ishrat Jahan
asked
in
Operating System
Nov 3, 2014
by
Ishrat Jahan
13.9k
views
gateit-2005
operating-system
disk
normal
45
votes
3
answers
201
GATE IT 2005 | Question: 81-a
A disk has $8$ equidistant tracks. The diameters of the innermost and outermost tracks are $1$ cm and $8$ cm respectively. The innermost track has a storage capacity of $10$ MB. What is the total amount of data that can be stored on the disk if it is used with a drive that rotates ... . $80 \ \text{MB}$; II. $360 \ \text{MB}$ I. $360 \ \text{MB}$; II. $80 \ \text{MB}$
Ishrat Jahan
asked
in
Operating System
Nov 3, 2014
by
Ishrat Jahan
11.9k
views
gateit-2005
operating-system
disk
normal
30
votes
1
answer
202
GATE IT 2005 | Question: 63
In a computer system, four files of size $11050$ bytes, $4990$ bytes, $5170$ bytes and $12640$ bytes need to be stored. For storing these files on disk, we can use either $100$ byte disk blocks or $200$ byte disk blocks (but can't mix ... blocks respectively? $35400$ and $35800$ bytes $35800$ and $35400$ bytes $35600$ and $35400$ bytes $35400$ and $35600$ bytes
Ishrat Jahan
asked
in
Operating System
Nov 3, 2014
by
Ishrat Jahan
6.4k
views
gateit-2005
operating-system
disk
normal
62
votes
5
answers
203
GATE IT 2007 | Question: 44, ISRO2015-34
A hard disk system has the following parameters : Number of tracks $= 500$ Number of sectors/track $= 100$ Number of bytes /sector $= 500$ Time taken by the head to move from one track to adjacent track $= 1 \ ms$ Rotation speed $= 600 \ rpm$. What is ... time taken for transferring $250$ bytes from the disk ? $300.5 \ ms$ $255.5 \ ms$ $255 \ ms$ $300 \ ms$
Ishrat Jahan
asked
in
Operating System
Oct 29, 2014
by
Ishrat Jahan
22.9k
views
gateit-2007
operating-system
disk
normal
isro2015
38
votes
2
answers
204
GATE CSE 1996 | Question: 23
A file system with a one-level directory structure is implemented on a disk with disk block size of $4K$ ... What is the maximum possible number of files? What is the maximum possible file size in blocks
Kathleen
asked
in
Operating System
Oct 9, 2014
by
Kathleen
9.8k
views
gate1996
operating-system
disk
normal
file-system
descriptive
39
votes
2
answers
205
GATE CSE 1995 | Question: 14
If the overhead for formatting a disk is $96$ bytes for a $4000$ byte sector, Compute the unformatted capacity of the disk for the following parameters: Number of surfaces: $8$ Outer diameter of the disk: $12$ cm Inner diameter of ... rpm, determine the effective data transfer rate which is defined as the number of bytes transferred per second between disk and memory.
Kathleen
asked
in
Operating System
Oct 8, 2014
by
Kathleen
12.9k
views
gate1995
operating-system
disk
normal
descriptive
32
votes
2
answers
206
GATE CSE 1993 | Question: 7.8
The root directory of a disk should be placed at a fixed address in main memory at a fixed location on the disk anywhere on the disk at a fixed location on the system disk anywhere on the system disk
Kathleen
asked
in
Operating System
Sep 29, 2014
by
Kathleen
13.2k
views
gate1993
operating-system
disk
normal
27
votes
5
answers
207
GATE CSE 1993 | Question: 6.7
A certain moving arm disk storage, with one head, has the following specifications: Number of tracks/recording surface $= 200$ Disk rotation speed $= 2400$ rpm Track storage capacity $= 62,500$ bits The average latency of this device is $\text{P}$ ms and the data transfer rate is $\text{Q}$ bits/sec. Write the values of $\text{P}$ and $\text{Q}$.
Kathleen
asked
in
Operating System
Sep 29, 2014
by
Kathleen
20.2k
views
gate1993
operating-system
disk
normal
descriptive
45
votes
2
answers
208
GATE CSE 2012 | Question: 41
A file system with $300$ GByte disk uses a file descriptor with $8$ direct block addresses, $1$ indirect block address and $1$ doubly indirect block address. The size of each disk block is $128$ Bytes and the size of each disk block address is $8$ Bytes. ... file size in this file system is $3$ KBytes $35$ KBytes $280$ KBytes dependent on the size of the disk
Arjun
asked
in
Operating System
Sep 29, 2014
by
Arjun
20.7k
views
gatecse-2012
operating-system
disk
normal
40
votes
1
answer
209
GATE CSE 2011 | Question: 44
An application loads $100$ libraries at startup. Loading each library requires exactly one disk access. The seek time of the disk to a random location is given as $10$ ms. Rotational speed of disk is $6000$ rpm. If all $100$ libraries are loaded from random locations on the disk, how ... start of the block may be neglected.) $0.50 \ s$ $1.50 \ s$ $1.25 \ s$ $1.00 \ s$
go_editor
asked
in
Operating System
Sep 29, 2014
by
go_editor
13.2k
views
gatecse-2011
operating-system
disk
normal
55
votes
5
answers
210
GATE CSE 2014 Set 2 | Question: 20
A FAT (file allocation table) based file system is being used and the total overhead of each entry in the FAT is $4$ bytes in size. Given a $100 \times 10^6$ bytes disk on which the file system is stored and data block size is $10^3$ bytes, the maximum size of a file that can be stored on this disk in units of $10^6$ bytes is _________.
go_editor
asked
in
Operating System
Sep 28, 2014
by
go_editor
20.6k
views
gatecse-2014-set2
operating-system
disk
numerical-answers
normal
file-system
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