A Pure Aloha transmits 200 bits frame on a shared channel of 200 kbps.What is time required to make Collision free?

Question

A Pure Aloha transmits 200 bits frame on a shared channel of 200 kbps.What is time required to make Frame Collision free?

Answer 1

Average Frame Transmission time T_fr is 200 bits/200 kbps or 1ms. 

The vulnerable time is 2 X 1ms= 2ms. 

This means no station should send later than 1ms before this station starts transmission and no station should start sending during the one 1- ms period that this station is sending. 

Source:Behrouz A Forouzan 

Comments

What is time required to make Frame Collision free?

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Read thru d descp given here. This contains a screen shot from Forouzan. I have taken d screen shot of d solution and straight away copied d solution as well. :) 

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I am understanding dear sir but what is the actual time required to make Frame Collision free??

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i think the actual time required to ensure that the frame does not collide is called vulnearable time. and vulnearable time is 2 ms here. so in terms of time ans is 2ms...?

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debasree88 Yes.