Lets try them in some real sentences,
suppose, $P(x) =$ $function$ which returns $true$ if $x$ is $even$ else returns $false$.
and, $W =$ $function$ which returns $true$ if it rained today else returns $false$ (lets call it $Rain()$)
Now, in option $C$ we have,
$LHS$ : For all the individual $x$ (either that particular $x$ is odd or $Rain()$)
$RHS$ : either there exists a odd number $x$ or $Rain()$.
An example where $LHS$ and $RHS$ are different:
set of $x = \{2,3, 4\}$
$LHS = Rain()\ and\ True\ and\ Rain()$ ($and$ because it must be true for all $x$)
$RHS = True$ (since 3 is in the set and is odd)
Now if it didn't rain today, then $LHS$ will become $False$ hence it cannot be equal to $RHS$ which is definitely $True$.
(Note, LHS and RHS should be equal for all possible values of $Rain()$ and it clearly isn't same if $Rain()$ returned $false$)
Lets check option $A$,
$LHS$ : For all the individual $x$ (either that particular $x$ is even or $Rain()$)
$RHS$ : either all of the $x$ are even or $Rain()$.
Lets try them on the same set as in previous case:
set of x = $\{2,3,4\}$
$LHS$ = $True\ and\ Rain()\ and\ True$ = $Rain()$
$RHS$ = $Rain()$
Here $LHS$ = $RHS$ (but maybe we didn't try hard enough to come up with a counter-example where they are not valid, you may try any possible set of $x$ and you will notice they will always be valid, there are only $3$ more cases to try, I will leave that as an exercise)