in Graph Theory
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7 votes
7 votes

How many non-isomorphic simple graph are there with N vertices, where N = 4 ?

in Graph Theory
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4 Comments

Should be 11.
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@Mk Utkarsh

Bhai did you read the page of the link you shared? It's too big and it get over my understanding... If you can explain in short, it would be nice
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What is the formula to find the non isomorphic graphs
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2 Answers

17 votes
17 votes
Best answer

Maximum number of edges possible with 4 vertices = $\binom{4}{2} = 6$. So, we take each number of edge one by one and examine.

The possible non isomorphic graphs with 4 vertices are as follows. All other possibilities you may think of, are isomorphic to one of the following graphs.

Answer: 11

Pardon me for the drawings.

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2 Comments

it should be 7 right? y 11?
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Please explain why 7?
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0 votes
0 votes

Answer should be 10. 

Since the number of vertices is 4, the maximum number of vertices can be 6.

With 0 edges - 1

with 1 edge -1

with 2 edges - 2

with 3 edges - 2

with 4 edges - 2

with 5 edges - 1

with 6 edges - 1

If anyone finds any mistake in my answer , please do mention it in the comment.

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1 comment

for 3 edges 3 nonisomorphic are possible
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