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Can you post a clearer picture
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1 Answer

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var(X) in exponential distribution is 1/(parameter)2 i.e 1/λ2 here so option B

var(3X+5)

⇒3var(X) + var(5)

⇒3*1/λ2 + 0                    as var(constant)=0;var(X)=1/λ2

⇒3/λ2

so option B

3 Comments

can you please explain the first question how it is (1/(parameter)^2)?
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now you can evaluate the integral to arrive at desired result.you can find this proof in any standard book for variance the formula is var(X) =E[x2]-(E[x])2

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var[3x+5]=var[3x]+var[5]
=3^2var[x]+0
= 9/λ2
I think this should be answer.

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