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Remove Left recursion from context free grammer
rahuldb
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Compiler Design
Jan 31, 2017
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rahuldb
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S -> Aa/Sa/c
A -> Ab/Sd/e
after substituting the value of S in terms of A
S -> Aa/Sa/c;
A -> Ab/ Aad/e/Aaa/ca;
after removing left recursion
S -> cS'/ AaS';
S' -> aS'/epsilon;
A -> eA'/caA'
A' -> bA'/adA'/aaA'/epsilon
$ruthi
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Aug 10, 2017
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Manu22
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Mar 2, 2018
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How did you get Aaa and ca after substituting the value of S in terms of A in the second production?
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