GATE CSE 2017 Set 2 | Question: 1

Question

The representation of the value of a $16\text{-bit}$ unsigned integer $X$ in hexadecimal number system is $\textsf{BCA9}$. The representation of the value of $X$ in octal number system is

• A. $571244$
• B. $736251$
• C. $571247$
• D. $136251$

Comments

answer is d

Answer 1

Given: $\textsf{(BCA9)}_{16}$

$1011\quad 1100\quad 1010\quad 1001$

For octal number system: grouping of three- three bits from right to left

$\begin{array}{c c c c c c } 1 & 011 & 110 & 010 & 101 & 001 \\ 1 & 3 & 6 & 2 & 5 & 1 \end{array}$

Answer: option D) $(1 3 6  2 5 1)_{8}$

Answer 2

BCA9 can be written as 1011 1100 1010 1001 .

Now keep taking 3 bits from lsb and convert to decimal. thus answer would be option D.

Answer 3

D should be the answer.

just convert hexadecimal into binary , it will be 1011 1100 1010 1001 now make group of 3 from LSB .

u need to add 2 zeros. and then write it in octal form. D will come out to be answer.

Comments

not from lhs from lsb dude

Answer 4

B          C     A      9 - Hex form

1011  1100 1010 1001 - Hex representation

 001 011 110 010 101 001 - group into three's for octal

136251

Answer is D