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The pre-order traversal of a binary search tree is given by $12, 8, 6, 2, 7, 9, 10, 16, 15, 19, 17, 20$. Then the post-order traversal of this tree is

  1. $2, 6, 7, 8, 9, 10, 12, 15, 16, 17, 19, 20$
  2. $2, 7, 6, 10, 9, 8, 15, 17, 20, 19, 16, 12$
  3. $7, 2, 6, 8, 9, 10, 20, 17, 19, 15, 16, 12$
  4. $7, 6, 2, 10, 9, 8, 15, 16, 17, 20, 19, 12$
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4 Comments

ans is B

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Should we need to create a in order... Can we just make a tree by using bst properties???
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edited by
Yes we can construct a unique BST by given exactly one of postorder/preorder using BST properties. No need to find inorder.

@rahul your method will not work in this question: https://gateoverflow.in/3816/gate-it-2005-question-55
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5 Answers

–1 vote
–1 vote
B) is the answer
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