program output

Question

char *c[] = {"GeksQuiz", "MCQ", "TEST", "QUIZ"};

char **cp[] = {c+3, c+2, c+1, c};

char ***cpp = cp;

int main()
{
    printf("%s ", **++cpp);
    
    printf("%s ", *--*++cpp+3);
    
    printf("%s ", *cpp[-2]+3);
    
    printf("%s ", cpp[-1][-1]+1);
    
    return 0;

}

Answer 1

code:

#include <stdio.h>

char *c[] = {"GeksQuiz","MCQ","TEST","QUIZ"};
char **cp[] = {c+3,c+2,c+1,c};
char ***cpp = cp;

int main(int argc, char const *argv[]) {

	printf("%s ",**++cpp);					// *(*(++cpp))	
	printf("%s ",*--*++cpp + 3);		// *(--(*(++cpp))) + 3
	printf("%s ",*cpp[-2] + 3); 		// *(*(cpp - 2)) + 3
	printf("%s ",cpp[-1][-1] + 1); 	// *(*(cpp - 1) - 1) + 1

	return 0;
}

Before main(): assumed pointer size 4 bytes and char size 1 byte

Now,

The following precedence rules will be used.

And ptr = ptr + x,   will set ptr to   ptr + x*sizeof(*ptr).

First printf:

Second printf:

Third printf:

Fourth printf:

Similar QS

Comments

Wonderful explanation...

---

awesome explanation !!

---

What if we had  printf("%c" ,***++cpp+2);, then what would have been the output ??

---

ksQuiz

Answer 2

op: TEST sQuiz Z CQ

Answer 3

OUTPUT : TEST, sQuiz,Z,CQ. for complete solution visit this link https://drive.google.com/open?id=0B9FSROwjRRdqcTlqNTBLQnhQQ28