What is the minimum number of two-input $\text{NAND}$ gates used to perform the function of two-input $\text{OR}$ gate?
Need only 3 NAND Gate : A+B = ((A + B)')' = ( A' .B' )'
I think answer is 1. Since it is asked minimum number of NAND GATE and also it is not mentioned that we should use only the NAND GATEs.......so we can use 1 NAND GATE and two NOT GATEs...but if maximum numbers of NAND GATEs would have been asked...then the answer would have been 3.
so by using 3 NAND gate we can perform OR gate operation
4
For NOT gate only 1 NAND & NOR gate are enough to realize.
& IF from 2 Input NAND gate we want to realize n-input NAND gate then it will be 2n-3.
64.3k questions
77.9k answers
244k comments
80.0k users