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9 votes
9 votes

What is the minimum number of two-input $\text{NAND}$ gates used to perform the function of two-input $\text{OR}$ gate?

  1. One
  2. Two
  3. Three
  4. Four
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It is direct question.

Ans =3
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4 Answers

14 votes
14 votes
Best answer

Need only 3 NAND Gate : A+B = ((A + B)')' = ( A' .B' )'

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4 Comments

I think answer is 1. Since it is asked minimum number of NAND GATE  and also it is not mentioned that we should use only the NAND GATEs.......so we can use 1 NAND GATE and two NOT GATEs...but if maximum numbers of NAND GATEs would have been asked...then the answer would have been 3.

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Question doesn't say that we can use another gate except Nand gate.
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In th question it is just asked minimum no. of NAND Gates....It is not said that we are bound to use only NAND gates.
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ok thankyou :)
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5 votes
5 votes
  by using NAND by using NOR
NOT 1 1
OR 3 2
AND 2 3
NAND - 4
NOR 4 -
EX-OR 4 5
EX-NOR 5 4

so by using 3 NAND gate we can perform OR gate operation

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@pawan KumarIn Sir, if we have gates with different fan-in and fan-out. will this table be same....?

This table is standard for 2 fan-in and 2 fan-out...?
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3 votes
3 votes
Gate Min NAND MIn NOR
AND 2 3
OR 3 2
NAND 1 4
NOR 4 1
EX-OR 4 5
EX-NOR 5

4

For NOT gate only 1 NAND & NOR gate are enough to realize.

& IF from 2 Input NAND gate we want to realize n-input NAND gate then it will be 2n-3. 

0 votes
0 votes
3 nand gates for or and 2 for and.
Answer: