Test by Bikram | Programming | Test 2 | Question: 8

Question

What is the output of this program?

#include <stdio.h>
int main()
{
char *ptr;
char string[] = "How are you?";
ptr = string;
ptr += 4;
printf("%s",ptr);
return 0;
}

• A. How are you?
• B. are you?        
• C. are      
• D. error in program

Answer 1

here 1) ptr = string;  : it will point to base address of string .

now  2) ptr += 4 ;  : it means ptr = ptr + 4*(size of char data type) = ptr + 4*(1) = it will point 4th index of char array (that is a) .

3)printf("%s",ptr);  :  %s will print the content of array untill it finds null. (that is "are you?") .

so ans would be B.

Comments

Space by 00010000 and NULL by 00000000 in binary assuming ASCII representation which is decided by the environment.

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what will be the output if : 

printf("%s",*ptr);

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if you will write ( “ %c” , *ptr) ; it will print a but i think in your case it will give some error . coz ptr is char type

Answer 2

scanf() doesn't recognise spaces, but printf() can.

Be careful about differentiating space and NULL character, though.

A NULL character, if not explicitly specified, can only be at the end.

 

Here, are you? will be printed, not just are. printf() recognises spaces.

After are you? there's an implicit NULL character (\0). This is how printf() knows when to stop. So, it'll stop after printing are you?

 

Option B