Test by Bikram | Programming | Test 2 | Question: 21

Question

What is the output of the following code snippet?  

#include <stdio.h>
int main()
{
char c=125;
c=c+10;
printf("%d",c);
return 0;
}

 

Answer 1

Char is of 1 Byte

range of singed char = {-2^n -1 to +2^n-1} = -128 to +127

char c =125

125+1= 126

125+2= 127

125+3=-128

125+4=-127

125+5=-126

125+6=-125

125+7=-124

125+8=-123

125+9=-122

125+10=-121

Comments

Opsss.... silly question....

Answer 2

(125= 01111101) + (10=00001010) = 10000111... showing overflow as addition of two positive numbers giving negative result.
Content of register = 10000111= -121 ( -2^7 + 7)

Comments

Nice :)